Integrand size = 26, antiderivative size = 79 \[ \int \frac {\sqrt {a^2+2 a b x^3+b^2 x^6}}{x^7} \, dx=-\frac {a \sqrt {a^2+2 a b x^3+b^2 x^6}}{6 x^6 \left (a+b x^3\right )}-\frac {b \sqrt {a^2+2 a b x^3+b^2 x^6}}{3 x^3 \left (a+b x^3\right )} \]
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Time = 0.01 (sec) , antiderivative size = 79, normalized size of antiderivative = 1.00, number of steps used = 3, number of rules used = 2, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.077, Rules used = {1369, 14} \[ \int \frac {\sqrt {a^2+2 a b x^3+b^2 x^6}}{x^7} \, dx=-\frac {a \sqrt {a^2+2 a b x^3+b^2 x^6}}{6 x^6 \left (a+b x^3\right )}-\frac {b \sqrt {a^2+2 a b x^3+b^2 x^6}}{3 x^3 \left (a+b x^3\right )} \]
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Rule 14
Rule 1369
Rubi steps \begin{align*} \text {integral}& = \frac {\sqrt {a^2+2 a b x^3+b^2 x^6} \int \frac {a b+b^2 x^3}{x^7} \, dx}{a b+b^2 x^3} \\ & = \frac {\sqrt {a^2+2 a b x^3+b^2 x^6} \int \left (\frac {a b}{x^7}+\frac {b^2}{x^4}\right ) \, dx}{a b+b^2 x^3} \\ & = -\frac {a \sqrt {a^2+2 a b x^3+b^2 x^6}}{6 x^6 \left (a+b x^3\right )}-\frac {b \sqrt {a^2+2 a b x^3+b^2 x^6}}{3 x^3 \left (a+b x^3\right )} \\ \end{align*}
Time = 1.01 (sec) , antiderivative size = 37, normalized size of antiderivative = 0.47 \[ \int \frac {\sqrt {a^2+2 a b x^3+b^2 x^6}}{x^7} \, dx=-\frac {\sqrt {\left (a+b x^3\right )^2} \left (a+2 b x^3\right )}{6 x^6 \left (a+b x^3\right )} \]
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Result contains higher order function than in optimal. Order 9 vs. order 2.
Time = 0.06 (sec) , antiderivative size = 22, normalized size of antiderivative = 0.28
method | result | size |
pseudoelliptic | \(-\frac {\operatorname {csgn}\left (b \,x^{3}+a \right ) \left (2 b \,x^{3}+a \right )}{6 x^{6}}\) | \(22\) |
gosper | \(-\frac {\left (2 b \,x^{3}+a \right ) \sqrt {\left (b \,x^{3}+a \right )^{2}}}{6 x^{6} \left (b \,x^{3}+a \right )}\) | \(34\) |
default | \(-\frac {\left (2 b \,x^{3}+a \right ) \sqrt {\left (b \,x^{3}+a \right )^{2}}}{6 x^{6} \left (b \,x^{3}+a \right )}\) | \(34\) |
risch | \(\frac {\left (-\frac {b \,x^{3}}{3}-\frac {a}{6}\right ) \sqrt {\left (b \,x^{3}+a \right )^{2}}}{x^{6} \left (b \,x^{3}+a \right )}\) | \(35\) |
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none
Time = 0.26 (sec) , antiderivative size = 13, normalized size of antiderivative = 0.16 \[ \int \frac {\sqrt {a^2+2 a b x^3+b^2 x^6}}{x^7} \, dx=-\frac {2 \, b x^{3} + a}{6 \, x^{6}} \]
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Timed out. \[ \int \frac {\sqrt {a^2+2 a b x^3+b^2 x^6}}{x^7} \, dx=\text {Timed out} \]
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none
Time = 0.22 (sec) , antiderivative size = 86, normalized size of antiderivative = 1.09 \[ \int \frac {\sqrt {a^2+2 a b x^3+b^2 x^6}}{x^7} \, dx=\frac {\sqrt {b^{2} x^{6} + 2 \, a b x^{3} + a^{2}} b^{2}}{6 \, a^{2}} + \frac {\sqrt {b^{2} x^{6} + 2 \, a b x^{3} + a^{2}} b}{6 \, a x^{3}} - \frac {{\left (b^{2} x^{6} + 2 \, a b x^{3} + a^{2}\right )}^{\frac {3}{2}}}{6 \, a^{2} x^{6}} \]
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none
Time = 0.32 (sec) , antiderivative size = 30, normalized size of antiderivative = 0.38 \[ \int \frac {\sqrt {a^2+2 a b x^3+b^2 x^6}}{x^7} \, dx=-\frac {2 \, b x^{3} \mathrm {sgn}\left (b x^{3} + a\right ) + a \mathrm {sgn}\left (b x^{3} + a\right )}{6 \, x^{6}} \]
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Time = 8.17 (sec) , antiderivative size = 33, normalized size of antiderivative = 0.42 \[ \int \frac {\sqrt {a^2+2 a b x^3+b^2 x^6}}{x^7} \, dx=-\frac {\left (2\,b\,x^3+a\right )\,\sqrt {{\left (b\,x^3+a\right )}^2}}{6\,x^6\,\left (b\,x^3+a\right )} \]
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